Chemistry High School
Answers
Answer 1
Answer:
2HNO3(aq)+Sr(OH)2(aq)⇌Sr(NO3)2(aq)+2H2O(l)
Explanation:
Answer 2
The transfer of one H+ ion and one OH- ion occurs in this reaction, and the resulting solution is neutral. the correct answer is:
CH_3CO_2H(aq) + NaOH(aq) ⇌ NaCH3_CO_2(aq) + H_2O(l)
What is the point of a neutral solution?
Neutral solutions have the same concentrations of hydrogen and hydroxide ions. A sodium chloride solution or a sugar solution could be used as a neutral solution. A neutral solution has a pH of 7. Water is another common material with a pH of neutral.
The concentrations of H+ and OH- ions in a solution must be equal for it to be neutral.
When an acid and a base are combined in stoichiometrically equal amounts, the only reaction that produces a neutral solution is:
CH_3CO_2H(aq) + NaOH(aq) ⇌ NaCH_3CO_2(aq) + H_2O(l)
This is a neutralization reaction that occurs between acetic acid (CH_3CO_2H) and sodium hydroxide (NaOH), producing sodium acetate (NaCH_3CO_2) and water (H_2O).
To know more about the neutralization reaction visit:
https://brainly.com/question/15255706
#SPJ1
Related Questions
Climate change ________________ disrupted the ______________ level of biological organization by disrupting the match between ________________ and their local environment. plants and animals are responding to changes in concentrations of carbon dioxide, local temperatures, and b _____________ precipitation patterns.
Answers
Climate change profound effect disrupted the global level of biological organization by disrupting the match between plants and animals and their local environment.
Plants and animals are responding to changes in concentrations of carbon dioxide, local temperatures, and biological precipitation patterns.
For example, some species are shifting their ranges to new regions that are more hospitable to their survival. Others are adapting to their new environment by altering their physical characteristics or behavior. In some cases, species are facing extinction due to the inability to adapt.
Climate change is also contributing to the spread of invasive species, which can outcompete native species for resources, altering local habitats and biodiversity. Climate change will continue to have profound impacts on the global level of biological organization as long as the changing climate persists.
Know more about species here
https://brainly.com/question/13259455#
#SPJ11
what critical risk and success factors must starbucks manage?
Answers
As a business, Starbucks must manage several critical risks to ensure its success. One critical risk is the potential for increased competition from other coffee shops and cafes, which could impact its market share and profitability. Additionally, Starbucks must manage the supply chain and operational risks, such as disruptions in the coffee bean supply or issues with its payment systems.
To maintain its success, Starbucks must also manage several key success factors. One important factor is its ability to maintain and grow its customer base, through marketing campaigns and delivering a high-quality customer experience. Additionally, Starbucks must continually innovate and introduce new products and services to stay relevant and meet evolving customer needs. Effective management of these critical risks and success factors is essential for Starbucks to maintain its position as a leader in the coffee industry.
Learn more about Starbucks at brainly.com/question/11540013
#SPJ11
list the symmetry elements of the following molecules and name the point groups to which they belong: (a) naphthalene, (b) anthracene, (c) three dichlorobenzene isomers.
Answers
(a) The symmetry elements of naphthalene are a C2 rotation axis perpendicular to the plane of the molecule, a C2 rotation axis in the plane of the molecule passing through the center of the rings, and a horizontal mirror plane passing through the center of the molecule. Therefore, naphthalene belongs to the point group D2h.
(b) The symmetry elements of anthracene are a C2 rotation axis perpendicular to the plane of the molecule, a C2 rotation axis in the plane of the molecule passing through the center of the rings, and a horizontal mirror plane passing through the center of the molecule. Additionally, there are two vertical mirror planes that bisect the molecule along the long axis. Therefore, anthracene belongs to the point group C2h.
(c) The three dichlorobenzene isomers are 1,2-dichlorobenzene, 1,3-dichlorobenzene, and 1,4-dichlorobenzene. Each of these molecules has a C2 rotation axis perpendicular to the plane of the molecule and a horizontal mirror plane passing through the plane of the molecule. Therefore, all three molecules belong to the point group C2v.
Learn more about isomers here:
https://brainly.com/question/12796779
#SPJ11
How much silver was in the solution if all of the silver was removed as Ag metal by electrolysis for 0.40 hr with a current of 1.00 mA (1 mA = 10-3 A)?
Answers
The amount of silver that was in the solution before electrolysis was 1.61 x 10^{-3} g.
How does electrolysis work?
When an electric current is sent through a substance, electrolysis, a chemical reaction, takes place. As a substance undergoes a chemical reaction, an electron is either gained or lost.
In order to respond to this query, we must apply Faraday's law of electrolysis, which has the following equation:
moles of substance = (electric charge / Faraday's constant)
where the Faraday's constant, which equals 96,485 C/mol e-, measures the amount of electric charge per mole of electrons.
Now, we want to find the amount of silver
Calculate the amount of electric charge;
electric charge = current x time
electric charge = 0.001 A x (0.40 hr x 3600 s/hr) = 1.44 C
Using Faraday's constant, convert the electric charge to moles of electrons:
moles of electrons = electric charge / Faraday's constant
= 1.44 C / 96,485 C/mol e-
= 1.49 x 10^{-5} mol e-
moles of Ag+ = moles of electrons = 1.49 x 10^{-5} mol
The mass of Ag present initially:
mass of Ag = moles of Ag+ x molar mass of Ag
= 1.49 x 10^{-3} mol x 107.87 g/mol
= 1.61 x 10^{-3} g
To know more about the electrolysis visit:
https://brainly.com/question/12994141
#SPJ1
write a balanced net ionic equation for the reaction of nibr2(aq) with (nh4)2s(aq).
Answers
The balanced net ionic equation for the reaction of NiBr2(aq) with (NH4)2S(aq) is:
Ni2+(aq) + S2-(aq) → NiS(s)
Note that the spectator ions NH4+ and Br- do not participate in the reaction and are not included in the net ionic equation.
Spectator ions are ions that do not participate in a chemical reaction, meaning they do not undergo any chemical change during the reaction. They are present in both the reactants and the products and do not affect the outcome of the reaction.
Spectator ions can be identified by looking at the balanced chemical equation of the reaction and canceling out ions that appear on both sides of the equation.
Visit here to learn more about spectator ions brainly.com/question/28913274
#SPJ11
The balanced net ionic equation for the reaction of NiBr2(aq) with (NH4)2S(aq) is:
Ni2+(aq) + S2-(aq) → NiS(s)
Note that the spectator ions NH4+ and Br- do not participate in the reaction and are not included in the net ionic equation.
Spectator ions are ions that do not participate in a chemical reaction, meaning they do not undergo any chemical change during the reaction. They are present in both the reactants and the products and do not affect the outcome of the reaction.
Spectator ions can be identified by looking at the balanced chemical equation of the reaction and canceling out ions that appear on both sides of the equation.
Visit here to learn more about spectator ions brainly.com/question/28913274
#SPJ11
For which mechanisms - SN1, SN2, E1, or E2 - does the mechanism involve carbocation intermediate? Select all that apply. SN1 E2 SN2 E1
Answers
The mechanisms that involve a carbocation intermediate are SN1 and E1.
SN1 (Substitution Nucleophilic Unimolecular) and E1 (Elimination Unimolecular) mechanisms both involve a carbocation intermediate. In an SN1 reaction, the leaving group departs first, forming a carbocation intermediate. This intermediate is then attacked by a nucleophile, leading to a substitution product.
In an E1 reaction, the leaving group also departs first, forming a carbocation intermediate. However, in this case, a base removes a neighboring hydrogen atom, resulting in an elimination product.
In contrast, SN2 (Substitution Nucleophilic Bimolecular) and E2 (Elimination Bimolecular) reactions do not involve carbocation intermediates, as they occur in a single concerted step without the formation of intermediates.
To know more about nucleophile click on below link:
https://brainly.com/question/31425447#
#SPJ11
The starting materials of dibenzalacetone synthesis are all colorless. which situation would have caused no change in color of the reaction mixture?
a. 1/ only one equivalent of benzaldehyde used in the reaction
b. 2/ presence of benzoic in the reaction mixture
c. 3/an excess of benzaldehyde present in the reaction mixture
Answers
The starting materials of dibenzalacetone synthesis are all colorless. A situation that would cause no change in color of the reaction mixture is c. 3/an excess of benzaldehyde present in the reaction mixture.
Excess benzaldehyde would not be completely consumed during the reaction, leaving a significant amount of unreacted colorless benzaldehyde in the final mixture. In contrast, using only one equivalent of benzaldehyde (option 1) may lead to incomplete reaction and formation of intermediate products, possibly resulting in a change of color.
Additionally, the presence of benzoic acid in the reaction mixture (option 2) could cause a change in color due to the formation of colored side products or interference with the reaction. Therefore, an excess of benzaldehyde in the reaction mixture is the most likely situation to cause no change in color of the dibenzalacetone synthesis reaction mixture. The starting materials of dibenzalacetone synthesis are all colorless. A situation that would cause no change in color of the reaction mixture is c. 3/an excess of benzaldehyde present in the reaction mixture.
Learn more about benzoic acid at:
https://brainly.com/question/28326761
#SPJ11
Why is the infrared absorption for the stretching motion of internal alkynes rarely observed?
options:
They do not form cations.
They are too strong.
There must be a change in dipole.
They don't have hydrogens.
Answers
The infrared absorption for the stretching motion of internal alkynes is rarely observed because they do not have hydrogens.
Hydrogens that participate in the stretching motion, and a change in dipole is required for infrared absorption to occur. Infrared absorption requires a change in dipole moment, which occurs when there is a change in the distribution of electron density in the molecule. In the case of internal alkynes, the carbon-carbon triple bond has a symmetric distribution of electron density, which does not change during stretching. Therefore, there is no dipole moment change and no infrared absorption is observed for the stretching motion of internal alkynes. Therefore, internal alkynes are not able to exhibit infrared absorption for their stretching motion.
Learn more about alkynes :
https://brainly.com/question/9620187
#SPJ11
unknown weak base with a concentration of .17m has a ph of 9.42. What is the Kb of this base? -
Answers
We can use the relationship between the pH, pOH, and Kb of a weak base:
Kb = (1.0 x 10^-14) / (OH^-)^2
First, we need to find the pOH of the solution, which is:
pOH = 14.00 - pH = 14.00 - 9.42 = 4.58
Next, we can find the concentration of hydroxide ions in the solution using the equation for the dissociation of water:
Kw = [H+][OH-] = 1.0 x 10^-14
[OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-9.42 = 3.98 x 10^-6 M
Now we can substitute these values into the Kb equation to solve for Kb:
Kb = (1.0 x 10^-14) / (3.98 x 10^-6)^2 = 6.29 x 10^-10
Therefore, the Kb of the unknown weak base is 6.29 x 10^-10.
Visit here to learn more about dissociation brainly.com/question/30961097
#SPJ11
how many grams of kno3are required to prepare 250ml of a .700m solution
Answers
To prepare 250 mL of a 0.700 M KNO3 solution, you will need to calculate the grams of KNO3 required. You will need 17.69 grams of KNO3 to prepare 250 mL of a 0.700 M solution.
To prepare a 250ml solution of 0.700m, you will need to use the formula:
molarity = moles of solute / liters of solution
First, let's calculate the number of moles of solute required:
moles of solute = molarity x liters of solution
moles of solute = 0.700m x 0.250L
moles of solute = 0.175 moles
Next, we need to convert moles of solute into grams of KNO3, using its molar mass:
molar mass of KNO3 = 101.1032 g/mol
grams of KNO3 = moles of solute x molar mass
grams of KNO3 = 0.175 moles x 101.1032 g/mol
grams of KNO3 = 17.6736 grams
Therefore, you will need 17.6736 grams of KNO3 to prepare 250ml of a 0.700m solution.
Learn more about solution here:
https://brainly.com/question/6566593
#SPJ11
Classify each of the following solutions as saturated, unsaturated, or supersaturated based on the following observations.
a. Agitation of the solution produces a large amount of solid crystals.
b. Heating the solution causes excess undissolved solute present to dissolve.
c. Excess undissolved solute is present at the bottom of the solution container.
d. The amount of solute dissolved is less than the maximum amount that could dissolve under the conditions at which the solution exists.
Answers
a. Agitation of the solution produces a large number of solid crystals that are supersaturated. b. Heating the solution causes excess undissolved solute present to dissolve unsaturated. c. The excess undissolved solute present at the bottom of the solution container is saturated. d. The amount of solute dissolved is less than the maximum amount that could dissolve under the conditions at which the solution exists is unsaturated.
a. The solution is supersaturated because agitation causes excess solute to come out of the solution and form crystals.
b. The solution is unsaturated because heating causes more solute to dissolve, indicating that less than the maximum amount is currently dissolved.
c. The solution is saturated because excess undissolved solute is present at the bottom of the container, indicating that the maximum amount of solute has dissolved under the current conditions.
d. The solution is unsaturated because the amount of solute dissolved is less than the maximum amount that could dissolve, indicating that more solute can still be added to the solution.
Learn more about solutions at brainly.com/question/30665317
#SPJ11
Label the different parts of the oxygen binding active site of hemoglobin. Fhelix Proximal Puckered histidine heme cofactor (His F8) A Iron metal HN B BR-group from amino acid in hemoglobin peptide Heme cofactor O, binding Movement of F helix Planar heme HN N-Fe?
Answers
When oxygen binds to the iron metal in the heme cofactor, it causes a movement of the F helix and a change in the planar structure of the heme.
In the oxygen binding active site of hemoglobin, the key components are as follows:
1. F helix: A helical structure in the hemoglobin that plays a crucial role in oxygen binding and releasing.
2. Proximal histidine (His F8): An amino acid residue located on the F helix that binds to the iron metal in the heme cofactor.
3. Heme cofactor: A ring-like structure containing an iron metal, responsible for binding oxygen.
4. Iron metal (Fe): The central atom in the heme cofactor that directly binds to oxygen.
5. BR-group: A part of the amino acid structure in the hemoglobin peptide that contributes to the overall structure and stability. When oxygen binds to the iron metal in the heme cofactor, it causes a movement of the F helix and a change in the planar structure of the heme. This movement and structural change enable hemoglobin to effectively carry and release oxygen throughout the body.
Learn more about amino acid :
https://brainly.com/question/1837143
#SPJ11
87. If two identical containers each hold the same gas at
the same temperature but the pressure inside one
container is exactly twice that of the other container,
what must be true about the amount of gas inside each
container?
Answers
Given two similarly-sized containers that contain identical gases at identical temperatures, if the pressure within one container is double that of the other, then consequently, the amount or quantity of gas within the higher-pressure receptacle must be twice as much.
What happens in the gas containes
This phenomenon can be explained using the renowned ideal gas law which remarkably affirms:
PV = nRT,
where P stands for the pressure, V for volume, n for mole number of the gas, R for a special constant and T for temperature.
Read more on gas laws here:https://brainly.com/question/4147359
#SPJ1
Given two similarly-sized containers that contain identical gases at identical temperatures, if the pressure within one container is double that of the other, then consequently, the amount or quantity of gas within the higher-pressure receptacle must be twice as much.
What happens in the gas containes
This phenomenon can be explained using the renowned ideal gas law which remarkably affirms:
PV = nRT,
where P stands for the pressure, V for volume, n for mole number of the gas, R for a special constant and T for temperature.
Read more on gas laws here:https://brainly.com/question/4147359
#SPJ1
what is the oxidation number of the carbon indicated by the arrow in the structure?
Answers
To determine the oxidation number of the carbon indicated by the arrow in the structure, we first need to know the general rule for assigning oxidation numbers. The oxidation number of an atom in a molecule reflects the number of electrons that atom would gain or lose if the molecule were to undergo complete ionization.
For carbon in organic molecules, the oxidation number is typically determined by assuming that each carbon atom forms four covalent bonds with other atoms (usually hydrogen or carbon). Each covalent bond represents two electrons, which are equally shared between the two atoms involved in the bond.
In the structure indicated by the arrow, the carbon atom is bonded to three other carbon atoms and one hydrogen atom. Each carbon-carbon bond represents two electrons, as does the carbon-hydrogen bond. Therefore, the carbon atom has a total of eight valence electrons from its bonds.
To calculate the oxidation number, we start with the assumption that the hydrogen atom has an oxidation number of +1 and each carbon-carbon bond is nonpolar, so each carbon atom involved in the bond has an oxidation number of zero.
We can then assign the oxidation number of the carbon atom indicated by the arrow by working backwards from the known total number of valence electrons. Since the carbon atom has four valence electrons, we can assume that it has either gained or lost electrons in order to reach an oxidation state that reflects a complete octet.
If we assume that the carbon atom has gained electrons, then its oxidation number would be negative. However, this is unlikely because carbon is more likely to lose electrons than gain them. Therefore, we can assume that the carbon atom has lost electrons, giving it a positive oxidation number.
Since the carbon atom has a total of eight valence electrons from its bonds and we assume that it has lost electrons, it must have an oxidation number of +4 in order to reflect a complete octet (since each valence shell of carbon contains four electrons). Therefore, the oxidation number of the carbon indicated by the arrow in the structure is +4.
Learn more about carbon here:
https://brainly.com/question/13719781
#SPJ11
List the following compounds in decreasing electronegativity difference.
Cl2, HCl, NaCl
Answers
In decreasing electronegativity difference, the order is NaCl, HCl, and [tex]Cl_2[/tex].
To list the compounds [tex]Cl_2[/tex], HCl, and NaCl in decreasing electronegativity difference, we must first determine the electronegativity values of each element involved:
- Chlorine (Cl) has an electronegativity of 3.16.
- Hydrogen (H) has an electronegativity of 2.20.
- Sodium (Na) has an electronegativity of 0.93.
Now, we can calculate the electronegativity differences for each compound:
1. HCl: The electronegativity difference is 3.16 (Cl) - 2.20 (H) = 0.96.
2. NaCl: The electronegativity difference is 3.16 (Cl) - 0.93 (Na) = 2.23.
3. [tex]Cl_2[/tex]: As both elements are the same, the electronegativity difference is 3.16 (Cl) - 3.16 (Cl) = 0.
To know more about "Electronegativity difference" refer here:
https://brainly.com/question/19577490#
#SPJ11
Consider the three Lewis structures of thiocyanate ion (SCN). Determine the formal charge for each atom in all the three resonance structures and use that result to choose which structure is more plausible. [:5-C=n:] [s=c=n:] [:S=C-N:1 (a) (b) Formal charges of atoms in (a) S N .N Formal charges of atoms in (b) S C С N Formal charges of atoms in (c) S The most plausible resonance structure is
Answers
The (a) is the most balanced and thus most plausible structure.
What is plausible structure?
Plausible structure is a way of organizing the components of a system, process, or idea in a way that makes sense and is reasonable. It involves taking into consideration the available data and analyzing it to form a cohesive structure. A plausible structure is important in order to ensure that all the components of the system, process, or idea work together in harmony and provide a reasonable outcome. It is also important to ensure that the structure is flexible enough to adjust to changing conditions and be able to adapt to future needs. Plausible structure is a fundamental component of engineering, design, and problem solving.
The most plausible resonance structure is (a), as it has the most balanced formal charges on each atom. In (a), the formal charges for S and N are both 0, while in (b) and (c), the formal charges for S and N are +1 and -1, respectively. Therefore, (a) is the most balanced and thus most plausible structure.
To learn more about plausible structure
https://brainly.com/question/13265914
#SPJ1
Calculate the pH at the equivalence point for the titration of 0.100 M methylamine (CH3NH2) with 0.100 M HCl. The Kb of methylamine is 5.0
Answers
Methylamine is a weak base, and hydrochloric acid (HCl) is a strong acid. The reaction between the two is:
CH3NH2 + HCl → CH3NH3+Cl-
At the equivalence point of the titration, the moles of HCl added will equal the moles of methylamine present in the solution. This means that all the methylamine will have been converted to its conjugate acid, CH3NH3+, and the solution will contain only CH3NH3+ and Cl- ions.
To calculate the pH at the equivalence point, we need to find the concentration of CH3NH3+ in the solution. This can be done by using the dissociation constant of the weak base, methylamine:
Kb = [CH3NH3+][OH-]/[CH3NH2]
At the equivalence point, [CH3NH2] = [CH3NH3+], so we can simplify the equation to:
Kb = [CH3NH3+]^2/[CH3NH2]
[CH3NH3+]^2 = Kb[CH3NH2]
[CH3NH3+] = sqrt(Kb[CH3NH2])
[CH3NH3+] = sqrt(5.0 x 10^-4 x 0.050)
[CH3NH3+] = 0.0224 M
Now we can use the equation for the ionization constant of a weak acid to find the pH:
Ka = [H+][A-]/[HA]
For the conjugate acid of methylamine, CH3NH3+, the Ka is:
Ka = Kw/Kb = 1.0 x 10^-14/5.0 x 10^-4 = 2.0 x 10^-11
At the equivalence point, [H+] = [CH3NH3+], so we can simplify the equation to:
Ka = [H+]^2/[CH3NH2+]
[H+]^2 = Ka[CH3NH2+]
[H+] = sqrt(Ka[CH3NH2+])
[H+] = sqrt(2.0 x 10^-11 x 0.0224)
[H+] = 4.2 x 10^-7 M
pH = -log[H+]
pH = -log(4.2 x 10^-7)
pH = 6.38
Therefore, the pH at the equivalence point of the titration of 0.100 M methylamine with 0.100 M HCl is 6.38.
*IG:whis.sama_ent*
Which of the following have at least one polar bond? Select all that apply.
O CCl4, O O2, O O=C=O, O CH3CH2CH3
Answers
[tex]CCl_4[/tex] and O=C=O have at least one polar bond. [tex]CH_3CH_2CH_3[/tex] and [tex]O_2[/tex] do not have polar bonds.
Out of the given options, [tex]CCl_4[/tex] and [tex]CO_2[/tex] have at least one polar bond.
In [tex]CCl_4[/tex] (carbon tetrachloride), each carbon-chlorine bond is polar due to the difference in electronegativity between carbon and chlorine atoms. However, the molecule as a whole is non-polar because the bond dipoles cancel each other out, resulting in a net dipole moment of zero.
In [tex]CH_3CH_2CH_3[/tex] (propane), each carbon-hydrogen bond is also polar due to the difference in electronegativity between carbon and hydrogen atoms. The molecule itself is non-polar, but it still contains polar bonds.
To learn more about polar bonds click here https://brainly.com/question/31324076
#SPJ11
what term describes the process when two liquids are completely soluble in each other in all proportions
Answers
The process by which two liquids are fully answerable in all proportions is appertained to as Miscible liquids.
A hom*ogeneous admixture is created when two liquids fully dissolve in each other. similar fluids are called miscible fluids.
Miscibility is the capability of two substances to blend fully and produce a hom*ogenous admixture. The term is generally applied to liquids, but it can also be used to describe feasts and solids.
Miscible liquids can mix in any rate. This means that no matter how important of one liquid we mix with how important of the other, the result will always be hom*ogeneous and free of meniscuses. The fractional distillation process separates them.
To know more about Miscible Liquids,
brainly.com/question/30650685
#SPJ4
draw the lewis structure for the sulfur trioxide so3 molecule. be sure to include all resonance structures that satisfy the octet rule.
Answers
The Lewis structure for sulfur trioxide (SO3) molecule can be drawn as follows:
O
//
O = S = O
\\
O
The two additional resonance structures are:
O
/ \\
O - S = O
\ //
O
O
//
O = S - O
//
O
In this Lewis structure, sulfur is the central atom and is bonded to three oxygen atoms through double bonds. Each oxygen atom has two lone pairs of electrons.
Sulfur trioxide is a resonance hybrid, meaning it can have multiple resonance structures that contribute to the overall structure of the molecule. The other resonance structures that satisfy the octet rule can be drawn by moving the double bond around each oxygen atom.
Learn more about The Lewis structure: https://brainly.com/question/20300458
#SPJ11
δg°' for the formation of udp–glucose from glucose-1-phosphate and utp is about zero. yet the production of udp–glucose is highly favorable. what is the driving force for this reaction?
Answers
The driving force for the formation of UDP-glucose from glucose-1-phosphate and UTP is the hydrolysis of the pyrophosphate bond in the reaction.
Although the standard free energy change (ΔG°') for the reaction is close to zero, the hydrolysis of the pyrophosphate bond provides a large negative ΔG value, which makes the overall reaction highly favorable. This energy released during the hydrolysis of the pyrophosphate bond is used to drive the formation of the UDP-glucose. Therefore, the hydrolysis of the pyrophosphate bond acts as the driving force for the formation of UDP-glucose.
Learn more about UDP-glucose: https://brainly.com/question/14925272
#SPJ11
what is the equilibrium expression for the following reaction? h2so4 (l) ⇌ so3 (g) h2o (l)
Answers
The equilibrium expression for the following reaction? h2so4 (l) ⇌ so3 (g) h2o (l): the final equilibrium expression for this reaction is: Kc = [SO3]
The equilibrium expression for the given reaction is:
Kc = [SO3][H2O] / [H2SO4]
where Kc is the equilibrium constant, [SO3], [H2O], and [H2SO4] are the molar concentrations of sulfur trioxide, water, and sulfuric acid respectively at equilibrium.
Hello! I'm happy to help with your question. The equilibrium expression for the reaction H2SO4 (l) ⇌ SO3 (g) + H2O (l) can be written using the equilibrium constant (Kc).
First, let's write the balanced chemical equation:
H2SO4 (l) ⇌ SO3 (g) + H2O (l)
Next, we'll write the equilibrium expression using the concentrations of the products and reactants:
Kc = [SO3] * [H2O] / [H2SO4]
In this expression, [SO3], [H2O], and [H2SO4] represent the equilibrium concentrations of the respective species. Keep in mind that only the concentrations of gases (SO3 in this case) are included in the equilibrium constant expression. Liquid concentrations, such as H2SO4 and H2O, do not affect the value of Kc.
So, the final equilibrium expression for this reaction is:
Kc = [SO3]
to learn more about equilibrium constant click here:
brainly.com/question/29359391
#SPJ11
in an experiment, it is found that 0.00124 mg of hexachlorobenzene (c6cl6) can be dissolved in 200 ml of water. what is the solubility of hcb in water in units of moles per liter?
Answers
The name zinc(II) chloride is correct, and the compound should not be renamed.
The compound zinc(II) chloride is incorrect because it does not properly reflect the actual chemical composition of the compound.
In this compound, zinc is present in its 2+ oxidation state, which means it has lost two electrons to become a cation. Chloride is present in its anionic form, having gained one electron to become a chloride ion.
According to the naming convention for ionic compounds, the cation's name is written first, followed by the anion's name, with the suffix ""-ide"" replacing the ending of the anion name. However, since zinc can form cations with different charges, the charge of the cation is indicated using Roman numerals in parentheses after the metal name.
Therefore, the correct name of this compound should be zinc(II) chloride, indicating that the zinc ion is in the +2 oxidation state.
If the compound actually had two chloride ions for each zinc ion, it would be correctly named zinc chloride, without the need for Roman numerals since zinc only has one possible oxidation state in this case.
In summary, the name zinc(II) chloride is correct, and the compound should not be renamed.
Click the below link, to learn more about Nomenclature of compounds:
https://brainly.com/question/25845195
#SPJ11
Digoxin is a drug that has been used to treat systolic heart failure for over 200 years. it has a therapeutic index value of 2.digoxin is a drug that has been used to treat systolic heart failure for over 200 years. it has a therapeutic index value of 2. Why is digoxin used in systolic heart failure?
Answers
Digoxin is used in systolic heart failure because it helps to increase the strength and efficiency of the heart's contractions, particularly in cases where the systolic function of the heart is impaired.
Digoxin works by inhibiting the sodium-potassium ATPase pump, which leads to an increase in intracellular calcium concentrations and subsequently improves the contractility of the heart. This makes it an effective treatment option for patients with systolic heart failure, as it can help to improve cardiac output and reduce symptoms such as shortness of breath and fatigue.
However, due to its narrow therapeutic index, careful monitoring is necessary to ensure that digoxin levels remain within a safe and effective range.
Learn more about Digoxin here:
https://brainly.com/question/12978309
#SPJ11
what happens to any grignard reagent that remians in the reaction mixture after addition of the aldehyde
Answers
Excess Grignard reagent in the reaction mixture will be destroyed by reacting with water or acidic workup solution, resulting in the formation of a salt or alcohol, making it necessary to ensure complete reaction with aldehyde.
After the addition of the aldehyde, any excess Grignard reagent that remains in the reaction mixture will react with water or the acidic workup solution. This reaction will destroy the Grignard reagent and result in the formation of a salt or alcohol. Therefore, it is important to ensure that all of the Grignard reagent has reacted with the aldehyde before proceeding with the workup. Any remaining Grignard reagent can also react with impurities in the reaction mixture, leading to unwanted side products.
Know more about Grignard Reagent here:
https://brainly.com/question/30144052
#SPJ11
What products would be obtained if aspartame were hydrolyzed completely in an aqueous solution of HCl? Hint, there is more than one hydrolyzable bond. Also consider acid/base equlibrium when drawing the
Answers
The hydrolysis of aspartame in an aqueous solution of HCl would result in the formation of its constituent amino acids, aspartic acid and phenylalanine, as well as methanol, and chloride ions. Acid/base equilibrium should be considered when drawing the reaction products.
If aspartame were completely hydrolyzed in an aqueous solution of HCl, several products would be obtained due to the presence of multiple hydrolyzable bonds. Aspartame contains two peptide bonds that can be hydrolyzed by acid. The hydrolysis of these bonds would result in the formation of the amino acids aspartic acid and phenylalanine. Additionally, aspartame contains an ester bond that can also be hydrolyzed by acid. This would result in the formation of methanol and the dipeptide aspartyl phenylalanine.
It is important to consider acid/base equilibrium when drawing the reaction mechanism for this hydrolysis. In an aqueous solution of HCl, the acid will dissociate into H+ and Cl- ions. The H+ ions will then react with the aspartame molecule, protonating the peptide bonds and ester bonds. This will make the bonds more susceptible to nucleophilic attack by water molecules, resulting in the hydrolysis of the bonds and the formation of the aforementioned products. The equilibrium of the reaction will depend on the concentration of the H+ ions and the rate of hydrolysis relative to the rate of the reverse reaction.
Learn more about aqueous solution here:
https://brainly.com/question/26856926
#SPJ11
Predict which element has the larger first ionization energy based on periodic trends.
a. Cs b. cannot be determined based on periodic trends
c. Sr
Answers
The correct answer is option c) Sr. We can predict that Sr will have a larger first ionization energy than Cs based on periodic trends.
The first ionization energy is the energy required to remove the outermost electron from an atom in the gas phase.
As we move from left to right across a period of the periodic table, the first ionization energy generally increases due to an increase in effective nuclear charge. The effective nuclear charge is the net positive charge experienced by an electron in an atom, taking into account the shielding effect of inner electrons.
As we move down a group of the periodic table, the first ionization energy generally decreases due to an increase in atomic radius and an increase in shielding effect.
Based on these periodic trends, we can predict that Sr (strontium) has a larger first ionization energy than Cs (cesium). This is because Sr is located to the right of Cs in the same period of the periodic table, and therefore has a higher effective nuclear charge. Additionally, Sr has a smaller atomic radius and less shielding effect compared to Cs, which further increases its first ionization energy.
Therefore, the correct answer is (c) Sr.
Learn more about periodic trends here: https://brainly.com/question/12074167
#SPJ11
What is the pOH of a solution with an H+ ion concentration of 4.37e-3?
Answers
Answer: The pOH of the solution is 11.64.
Explanation: The pH and pOH of a solution are related to the concentration of hydrogen ions ([H+]) and hydroxide ions ([OH-]) by the equation:
pH + pOH = 14
Therefore, we can first calculate the pH of the solution as follows:
pH = -log[H+]
pH = -log(4.37e-3)
pH = 2.36
Then, we can use the equation above to find the pOH:
pOH = 14 - pH
pOH = 14 - 2.36
pOH = 11.64
In the Bohr model of the one-electron atom, the electron travels in fixed orbits, the radii of which __ as the principal quantum number n increases and __ as the nuclear charge Z increases. decrease, increase The radii of the Bohr orbits are all equal to the Bohr radius. decrease, decrease increase, increaseincrease, decrease
Answers
In the Bohr model of the one-electron atom, the electron travels in fixed orbits around the nucleus, which are also called stationary states or energy levels. The Bohr model predicts that the radius.
these orbits is proportional to the principal quantum number n, which is a positive integer that determines the energy level of the electron. Specifically, the radius of the nth Bohr orbit is given by:
r_n = a_0 * n^2 / Z
where a_0 is the Bohr radius (a fundamental physical constant), Z is the nuclear charge (equal to the atomic number), and n is the principal quantum number.
From this equation, we can see that the radii of the Bohr orbits increase as the principal quantum number n increases. This means that electrons in higher energy levels are further away from the nucleus atom and have more energy.
On the other hand, the radius of the Bohr orbits decreases as the nuclear charge Z increases. This is because a larger nuclear charge attracts the electron more strongly, pulling it closer to the nucleus and reducing the size of the orbit. Thus, for a given principal quantum number n, the Bohr radius decreases as Z increases.
Learn more about atom here:
https://brainly.com/question/30898688
#SPJ11
a rate is equal to 0.0200 m/s. if [a] = 0.100 m and rate = k[a]0, what is the new rate if the concentration of [a] is increased to 0.400 m?
Answers
the new rate when the concentration of A is increased to 0.400 m remains the same as the initial rate, which is 0.0200 m/s.
We are given the following information:
1. The initial rate is 0.0200 m/s
2. The initial concentration of A, [A] = 0.100 m
3. The rate equation is given as rate = k[A]^0
Now, we need to find the new rate when the concentration of A, [A] is increased to 0.400 m.
Step 1: Since the rate equation is given as rate = k[A]^0, we can simplify it to rate = k because any number raised to the power of 0 is 1.
Step 2: Use the initial rate and initial concentration to find the value of k. We are given rate = 0.0200 m/s and [A] = 0.100 m, so:
0.0200 m/s = k
Step 3: Now that we have the value of k, we can use the new concentration of A, [A] = 0.400 m, to find the new rate. Plug in the new concentration into the rate equation:
New rate = k * (0.400 m)^0
Since anything raised to the power of 0 is 1, the equation becomes:
New rate = k
Step 4: Use the value of k from Step 2:
New rate = 0.0200 m/s
To know more about concentration refer to
https://brainly.com/question/17206790
#SPJ11
